(X+2)^2-2(x-3)=10

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Solution for (X+2)^2-2(x-3)=10 equation: 



(X+2)^2-2(X-3)=10

We move all terms to the left:

(X+2)^2-2(X-3)-(10)=0

We multiply parentheses

(X+2)^2-2X+6-10=0

We add all the numbers together, and all the variables

-2X+(X+2)^2-4=0

We move all terms containing X to the left, all other terms to the right

-2X+(X+2)^2=4

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